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Question

If the image of the point (1,1,1) by a plane (3,−1,5) then the equation of the plane is

A
xy+2z=8
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B
xy+2z=16
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C
xy+2z=14
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D
None of these
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Solution

The correct option is A xy+2z=8
Let A=(1,1,1) and A=(3,1,5)
So mid point of AA is (2,0,3)
and direction ratio of AA are 2,2 and 4.
Since A is the image of A so equation of plane is given by,
2(x2)2(y0)+4(z3)=0
xy+2z=8

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