If the image of the point (1,1,1) by a plane (3,−1,5) then the equation of the plane is
A
x−y+2z=8
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B
x−y+2z=16
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C
x−y+2z=14
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D
None of these
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Solution
The correct option is Ax−y+2z=8 Let A=(1,1,1) and A′=(3,−1,5) So mid point of AA′ is (2,0,3) and direction ratio of AA′ are 2,−2 and 4. Since A′ is the image of A so equation of plane is given by, 2(x−2)−2(y−0)+4(z−3)=0 ⇒x−y+2z=8