If the image of the point P(1,–2,3) in the plane, 2x+3y–4z+22=0 measured parallel to the line,x1=y4=z5isQ,thenPQ is equal to:
A
3√5
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B
2√42
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C
√42
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D
6√5
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Solution
The correct option is B2√42 Let midpoint of PQ be M which lies on the plane.
Equation of line PQ is (1,−2,3)+λ(1,4,5) ⇒LetM(x,y,z)=(1+λ,4λ−2,5λ+3)Putting this point in the equation of plane2(1+λ)+3(4λ−2)−4(5λ+3)+22=0⇒λ=1⇒M(2,2,8),P(1,−2,3)PQ=2×PM=2√42