If the incircle of $△ A B C$ touches the sides $A B, B C$ and $C A$ at $P, Q$ and $R$ , find the value of :
$A P + B Q + C R$

A B + B C + C A

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2 (A B + B C + C A)

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\frac{1}{2} (A B + B C + C A)

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A B - B C - C A

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Solution

The correct option is C $\frac{1}{2} (A B + B C + C A)$

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∣ ∣ ∣ ∣ \begin{matrix} - b c & c a + a b & c a + a b a b + b c & - c a & a b + b c b c + c a & b c + c a & - a b \end{matrix} ∣ ∣ ∣ ∣ = (\sum a b)^{3}

Question 58 (h)

Subtract:

2(ab + bc + ca) from -ab - bc - ca.

In the given figure, the incircle of $△ A B C$ touches the sides AB, BC and CA at the points P, Q, R respectively. Show that
$A P + B Q + C R = B P + C Q + A R$
$= \frac{1}{2} (P e r i m e t e r o f △ A B C)$
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In triangle ABC prove AB+BC+CA >2AB

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If the incircle of △ABC touches the sides AB,BC and CA at P,Q and R, find the value of :AP+BQ+CR

The correct option is C 12(AB+BC+CA)

If the incircle of $△ A B C$ touches the sides $A B, B C$ and $C A$ at $P, Q$ and $R$ , find the value of :
$A P + B Q + C R$

The correct option is C $\frac{1}{2} (A B + B C + C A)$