Question

If the increase kinetic energy of a body 300%, then per cent increase in its momentum is

• A. 50%
• B. 300%
• C. 100%
• D. 150%

Answer 1

The correct option is C 100%

Final $KE=4$ times initial $KE$
$KE=\frac{p^2}{2m}4KE=\frac{{p_1}^2}{2m}\Rightarrow {p_1}^2=4p^2\Rightarrow p_1=2p$

Therefore, percentage increase in it's momentum is $100$%.