If the inductance and capacitance are both doubled in L-C-R circuit, the resonant frequency of the circuit will :

Decrease to one-half of the original value

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Decrease to one-fourth of the original value

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Increase to twice the original value

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Decrease to twice the original value

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Solution

The correct option is A Decrease to one-half of the original value
Resonant frequency in series LCR circuit : $ω = \sqrt{\frac{1}{L C}}$
When L and C are doubled, $ω^{'} = \sqrt{\frac{1}{L^{'} C^{'}}} = \sqrt{\frac{1}{2 L \times 2 C}} = \frac{ω}{2}$

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If the inductance and capacitance are both doubled in L-C-R circuit, the resonant frequency of the circuit will :

The correct option is A Decrease to one-half of the original valueResonant frequency in series LCR circuit : ω=√1LCWhen L and C are doubled, ω′=√1L′C′=√12L×2C=ω2

The correct option is A Decrease to one-half of the original value
Resonant frequency in series LCR circuit : $ω = \sqrt{\frac{1}{L C}}$
When L and C are doubled, $ω^{'} = \sqrt{\frac{1}{L^{'} C^{'}}} = \sqrt{\frac{1}{2 L \times 2 C}} = \frac{ω}{2}$