Question

If the initial potential energy is zero, the energy at the mean position $(x=0)$ of simple harmonic oscillation will be

• A. Zero
• B. Partial PE and partial KE
• C. Totally KE
• D. Totally PE

Answer 1

The correct option is C Totally KE

$\text{KE}$ of a particle undergoing SHM $=\frac{1}{2}m{\omega }^2(A^2-x^2)$
$x=0,KE=\frac{1}{2}m{\omega }^2{A}^2=\text{Total energy}$
$\therefore \text{KE}$ is maximum at mean position i.e at $x=0$.