If the initial velocity of a projectile be doubled. Keeping the angle of projection same, the maximum height reached by it will

Remain the same

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Be doubled

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Be quadrupled

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Be halved

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Solution

The correct option is C Be quadrupled
$H = \frac{u^{2} s i n^{2} θ}{2 g} ∴ H \propto u^{2} [A s θ = c o n s t a n t]$
If initial velocity of a projectile be doubled then H will becomes 4 times.

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If the initial velocity of a projectile be doubled. Keeping the angle of projection same, the maximum height reached by it will

The correct option is C Be quadrupledH=u2sin2θ2g ∴H∝u2 [As θ=constant] If initial velocity of a projectile be doubled then H will becomes 4 times.

The correct option is C Be quadrupled
$H = \frac{u^{2} s i n^{2} θ}{2 g} ∴ H \propto u^{2} [A s θ = c o n s t a n t]$
If initial velocity of a projectile be doubled then H will becomes 4 times.