Question

If the instantaneous emf and the instantaneous current equations of an A.C. circuit are respectively
$e=E_0\sin (\omega t-\pi /6),i=I_0\sin (\omega t+\pi /6)$, then the phase difference between voltage and current is :

• A. $\frac{\pi }{3}$
• B. zero
• C. $\frac{\pi }{2}$
• D. $\frac{\pi }{6}$

Answer 1

The correct option is A $\frac{\pi }{3}$

Phase of current ${\varphi }_1=wt+\frac{\pi }{6}$

Phase of emf ${\varphi }_2=wt-\frac{\pi }{6}$

Phase difference $\Delta \varphi ={\varphi }_1-{\varphi }_2$

$⟹\Delta \varphi =(wt+\frac{\pi }{6})-(wt-\frac{\pi }{6})=\frac{\pi }{3}$