Question

If the interatomic spacing in a steel wire is $2.8\times {10}^{-10}m$ and $Y_{real}=2\times {10}^{11}N/m^2$, then force constant in N/m is -

• A. $5.6$
• B. $56$
• C. $0.56$
• D. $560$

Answer 1

Answer: (B)

$56$

$\begin{array}{cc}\text{Force constant}K,& =Y\times \text{normal distance between atoms}\\ & =2.8\times {10}^{-10}\times 2\times {10}^{11}\\ & =5.6\times 10\\ & =56N/m\\ \text{Hence answer is B}& \end{array}$