If the interior angle of a regular polygon exceeds the exterior angle by $132^{o}$ , then the number of sides of the polygon is

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Solution

The correct option is A 15
We know that
$i n t e r i o r a n g l e + e x t e r i o r a n g l e = 180^{0}$ $. . . . . . . (1)$

Since,
$e x t e r i o r a n g l e + 132^{0} + e x t e r i o r a n g l e = 180^{0}$
$2 (e x t e r i o r a n g l e) = 180^{0} - 132^{0}$
$2 (e x t e r i o r a n g l e) = 48^{0}$
$e x t e r i o r a n g l e = 24^{0}$

Therefore, the number of sides
$= \frac{360^{0}}{24^{0}}$
$= 15$

Hence, this is the answer.

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