If the interior angles of a pentagen measure x-x-10-x-20-2 x-44- and 2 x-70- then x-A- 30-B- 40-C- 50-D- 60-

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Quadrilateral

If the interi...

Question

If the interior angles of a pentagen measure $x^{\circ}, (x - 10)^{\circ}, (x + 20)^{\circ}, (2 x - 44)^{\circ}$ and $(2 x - 70)^{\circ}$ , then x = ___ .

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Solution

The correct option is A

Sum of interior angles of a n sided polygon = (2n - 4) x 90°

A pentagon has 5 sides.

Sum of interiar angles of a pentagon $= (10 - 4) \times 90^{\circ}$

$x + x - 10 + x + 20 + 2 x - 44 + 2 x - 70 = 6 (90^{\circ})$

$7 x - 104 = 540^{\circ}$

7x =644

x = 92°

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Similar questions

If the interior angles of a pentagen measure $x^{\circ}, (x - 10)^{\circ}, (x + 20)^{\circ}, (2 x - 44)^{\circ}$ and $(2 x - 70)^{\circ}$ , then x = ___ .

Q. If the interior angles of a pentagen measure x⁰, (x-10)⁰, (x+20)⁰, (2x-44)⁰ and (2x-70)⁰, then x = ___ .

The angles of a pentagen are $x^{\circ}, (x - 10)^{\circ}, (x + 20)^{\circ}, (2 x - 44)^{\circ}$ and $(2 x - 70)^{\circ}$ , then x=___

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The angles of a pentagon are $x^{\circ}, (x - 10)^{\circ}, (x + 20)^{\circ}, (2 x - 44)^{\circ}$ and $(2 x - 70)^{\circ}$ , then x=___

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If the interior angles of a pentagen measure x∘,(x−10)∘,(x+20)∘,(2x−44)∘ and (2x−70)∘, then x = ___ .

The correct option is A Sum of interior angles of a n sided polygon = (2n - 4) x 90° A pentagon has 5 sides. Sum of interiar angles of a pentagon =(10−4)×90∘ x+x−10+x+20+2x−44+2x−70=6(90∘) 7x−104=540∘ 7x =644 x = 92°

If the interior angles of a pentagen measure $x^{\circ}, (x - 10)^{\circ}, (x + 20)^{\circ}, (2 x - 44)^{\circ}$ and $(2 x - 70)^{\circ}$ , then x = ___ .

The correct option is A

Sum of interior angles of a n sided polygon = (2n - 4) x 90°

A pentagon has 5 sides.

Sum of interiar angles of a pentagon $= (10 - 4) \times 90^{\circ}$

$x + x - 10 + x + 20 + 2 x - 44 + 2 x - 70 = 6 (90^{\circ})$

$7 x - 104 = 540^{\circ}$

7x =644

x = 92°