Sum of the interior angles of a pentagon = 540∘
⇒(3x+4)°+(x+20)°+(3x−5)°+(2x+10)°+(4x−9)°=540∘ [1 Mark]
⇒13x+20∘=540∘ [1 Mark]
⇒13x=540∘−20∘
⇒x=52013
⇒x=40∘ [1 Mark]
If the interior angles of a pentagon are (3x + 4)°, (x + 20)°, (3x - 5)°, (2x + 10)° and (4x - 9)°, then x is equal to
If the angles of a quadrilateral are 4x°,2x+10°,3x+20°,x-20°, then find the angles.