If the internal energy of a system decreases by 128J and at the same time it absorbs 56J of heat, then
A
work is done by the system equal to +71J
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B
work is done by the system equal to −184J
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C
work is done by the system equal to −71J
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D
work is done by the system equal to 179J
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Solution
The correct option is B work is done by the system equal to −184J ΔU=q+W Internal energy decreases by 128J thus, ΔU=−128J Heat is absorbed, q=+56J Thus, W=ΔU−q=(−128−56)J=−184J