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Question

If the internal energy of an ideal gas decreases by the same amount as the work done by the system, the process is:

A
Cyclic
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B
Isothermal
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C
Adiabatic
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D
Isolated
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Solution

The correct option is C Adiabatic
The internal energy of the ideal gas decreases by the same amount as the work done by the system.
From the first law of thermodynamics,
change in internal energy = heat exchange + work done
i.e ΔU=q+w
For an adiabatic process q=0
change in internal energy = work done
i.e. it is adiabatic and the decrease in temperature take place.

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