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Question

If the ionisation energy of He+ is 19.6×1018J per atom then the energy of Be3+ in the 2nd stationary state is:

A
156.8×1017 J/atom
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B
15.68×1017 KJ/atom
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C
15.68×1017 J/atom
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D
none of these
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Solution

The correct option is D none of these
EαZ2n2
For ionization of He+
Z=2,n=1
E=19.6×1018J
For Be3+ in 2nd state
Z=4 n=2
E=Z2n2E

=164E=4E

=4×19.6×1018

=7.84×1017

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