If the ionization energy of hydrogen is 13.6 eV, then the ionization energy for ${H e}^{+}$ ion will be

-54.4 eV

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-6.8 eV

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+6.8 eV

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-3.4 eV

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Solution

The correct option is A -54.4 eV
IE=13.6z^2. where z is atomic no.
IE of He+ is 13.6*4
= -54.4ev

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