Question

If the ionization potential of hydrogen atom is 13.6 eV, then, find the ionization potential of $H{e}^{+}$ ion.

• A. $-54.4eV$
• B. $+54.4eV$
• C. $-13.6eV$
• D. $+13.6eV$

Answer 1

The correct option is B $+54.4eV$

$ForH{e}^{+}ion,E=\frac{Z^2{E}_1}{n^2}$
$ForH{e}^{+}ion,E_1=2^2\times \frac{-13.6}{1}$
$=-54.4eV$
$E_{\infty }-E_1=0+54.4eV=+54.4eV$
Ionization potential of $H{e}^{+}$ ion = $+54.4eV$