Question

If the Josephites soccer team won a total of c games this season and last season, and the team won b fewer games this season than last season, how many games did they win last season?

• A. $\frac{b-c}{2}$
• B. $\frac{c-b}{2}$
• C. $\frac{b+c}{2}$
• D. $b+\frac{c}{2}$
• E. $c+\frac{b}{2}$

Answer 1

Answer: (C)

$\frac{b+c}{2}$

Let the matches won this season be $x$ and last season be $y$. Then,

According to question

$x=y-b$

and

$x+y=c$

$y-b+y=c$

$2y=b+c$

$y=\frac{(b+c)}{2}$