If the kth term of the arithmetic progression 25, 50,75, 100, …… is 1000, then find the value of k.
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Solution
Let a be the first term and d be their common difference of the AP. Then, nth term of the AP Tn=a+(n−1)d Here, in the given AP,. a=25;d=50−25=25 Given, Tk=1000 =>25+(k−1)25=1000 =>25+25k−25=1000 =>25k=1000 =>k=40