If the Kinetic energy of a body in increased by 100% then the change in momentum of the body is :

4.14%

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41.4%

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141.7%

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none of these

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Solution

The correct option is B 41.4%
$K E = p^{2} / 2 m$
$2 K E = p^{' 2} / 2 m$
$p^{2} / m = p^{' 2} / 2 m$
$p^{'} = \sqrt{2} p$
Change= $(\sqrt{2} p - p) * 100 / p = (\sqrt{2} - 1) * 100 = 1.414 - 1 = 0.414 * 100 = 41.4$

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