Question

If the kinetic energy of a moving particle is E, then the de-Broglie wavelength is

• A. $\lambda =h\sqrt{2mE}$
• B. $\lambda =\sqrt{\frac{2mE}{h}}$
• C. $\lambda =\frac{h}{\sqrt{2mE}}$
• D. $\lambda =\frac{hE}{\sqrt{2mE}}$

Answer 1

The correct option is C $\lambda =\frac{h}{\sqrt{2mE}}$

$E=\frac{1}{2}m{v}^{2}or$

$mv=\sqrt{2mE}or$

$\lambda =\frac{h}{mv}=\frac{h}{\sqrt{2mE}}$