Question

If the kinetic energy of body is increased by 44% then how will its momentum

Answer 1

Dear Student

$$\begin{gathered} \frac{{\displaystyle \frac{1}{2}}m(v^2-u^2)}{{\displaystyle \frac{1}{2}}m{u}^2}=0.44 \\ \frac{v^2}{u^2}-1=0.44 \\ \frac{v^2}{u^2}=1.44 \\ \to \frac{v}{u}=1.2 \\ =\frac{mv}{mu}=1.2 \\ =\frac{mv}{mu}-1=1.2-1 \\ \frac{m∆v}{mu}=0.2 \\ Henceincreaseinmomentum=20\% \end{gathered}$$