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Byju's Answer
Standard VI
Mathematics
HCF
If the L.C.M ...
Question
If the L.C.M of 336 and 560 is 1680, then their G.C.D is
A
168
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B
112
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C
560
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D
1680
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Solution
The correct option is
B
112
336
=
2
×
2
×
2
×
2
×
3
×
7
560
=
2
×
2
×
2
×
2
×
5
×
7
L.C.M. =
1680
G.C.D. =
2
×
2
×
2
×
2
×
7
=
112
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0
Similar questions
Q.
The product of two numbers is
6912
and their GCD is
24
. What is their LCM?
Q.
The HCF of two number is
28
and their LCM is
336
. If one number is
112
then, the other number is
Q.
LCM of (2
3
× 3 × 5) and (2
4
× 5 × 7) is
(a) 40
(b) 560
(c) 1680
(d) 1120
Q.
The GCD of two polynomials is
x
y
2
z
2
and their LCM is
x
y
3
z
8
. If one of the polynomials is
x
y
2
z
2
, then the other one is
.
Q.
Let
a
1
,
b
1
,
c
1
be natural numbers. We define
a
2
=
g
c
d
(
b
1
,
c
1
)
,
b
2
=
g
c
d
(
c
1
,
a
1
)
,
c
2
=
g
c
d
(
a
1
,
b
1
)
,
and
a
3
=
l
c
m
(
b
2
,
c
2
)
,
b
3
=
l
c
m
(
c
2
,
a
2
)
,
c
3
=
l
c
m
(
a
2
,
b
2
)
.
Show that
g
c
d
(
b
3
,
c
3
)
=
a
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.
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