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Question

# If the largest member of the Pythagorean triplet is given to be 17, then find the other two members of the Pythagorean triplet.

A
15,16
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B
8,15
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C
8,16
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D
7,8
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Solution

## The correct option is B 8,15The three numbers that will form a Pythagorean triplet will be given as: 2m,m2−1, and m2+1, where m is any positive integer. Here, the largest member of the Pythagorean triplet is m2+1 and the smallest member is 2m. The three members of Pythagorean triplet can be represented as follows: It is given that the largest side of the Pythagorean triplet is 17. ∴m2+1=17m2=17−1m2=16m=±4 Since m is a positive integer, therefore m=4. Hence, the smallest member of the Pythagorean triplet is calculated as, Smallest member of the triplet=2m=2(4)=8 Furthermore, the last member of the triplet is m2−1=42−1=16−1=15 Thus, the three members of Pythagorean triplet are (8,15,17) and can be represented as, Hence, the other two members of the Pythagorean triplet are 8 and 15.

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