The correct option is B 4
Let a,d,n be the first term, common difference, and number of terms of the given AP respectively.
Given, last term =an=118
⇒a+(n−1)d=118 ...(1)
Again, 8th term from end=(n−8+1)th term from beginning.
i.e.8th term from end=(n−7)th term from beginning =90
⇒an−7=90
⇒a+(n−8)d=90 ...(2)
Subtracting (2) from (1), we get
7d=28⇒d=4
Hence, option B is correct.