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Question

If the last term of an A.P. is 118 and the 8th term from the end is 90, then the common difference of the A.P. is

A
2
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B
4
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C
3
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D
3
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Solution

The correct option is B 4
Let a,d,n be the first term, common difference, and number of terms of the given AP respectively.
Given, last term =an=118
a+(n1)d=118 ...(1)
Again, 8th term from end=(n8+1)th term from beginning.
i.e.8th term from end=(n7)th term from beginning =90
an7=90
a+(n8)d=90 ...(2)
Subtracting (2) from (1), we get
7d=28d=4
Hence, option B is correct.

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