If the latus rectum of an hyperbola be 8 and eccentricity be 3√5 , then the equation of the hyperbola is
4x2−5y2=100
5x2−4y2=100
4x2+5y2=100
5x2+4y2=100
2b2a=8 and 3√5=√1+b2a2 or 45=b2a2 ⇒a=5,b=2√5. Hence the required equation of hyperbola is x225−y220=1 ⇒4x2−5y2=100.