If the LCM of a and 18 is 36 and the HCF of a and 18 is 2, then a =

(a) 2
(b) 3
(c) 4
(d) 1

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Solution

LCM

HCF

We know that the product of numbers is equal to the product of their HCF and LCM.

Therefore,

Hence the correct choice is (c).

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^{18} C_{2 r} =^{18} C_{r + 3}

r

a + b + c = 18

a, b, c \in R^{+}

a^{2} b^{3} c^{4}

If $^{n} C r - 1$ = 36, $^{n} C r$ = 84 and $^{n} C r + 1$ = 126, then the value of r is

81, 18

36

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