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Question

If the LCM of the polynomials f(x)=(x+1)5(x+2)a and g(x)=(x+1)b(x+2)a is (x+1)a(x+2)b, then find the minimum value of a+b from the following options.

A
10
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B
14
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C
15
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D
Cannot say
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Solution

The correct option is A 10
f(x)=(x+1)5(x+2)a
g(x)=(x+1)b(x+2)5
LCM = (x+1)a(x+2)b
As (x+1)a is a multiple of both (x+1)5 and (x+1)b,a5 and ab .....(1)
As (x+2)b is a multiple of both (x+2)a and (x+2)5,b5 and ba ...........(2)
From equation 1 & 2,
a=b,a5 and b5
Therefore, minimum value of a+b is 5+5,i.e.,10.


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