If the length and breadth of a rectangle are doubled, how many times the perimeter of the new rectangle be that of the original rectangle ?

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Solution

Original Dimensions = l,b
Original perimeter = 2(l+b)
New Dimensions = 2l, 2b
New perimeters = 2(2l+2b)
=4(l+b)
New perimeter is 2 times the old perimeter

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