Question

If the length and width of a photo frame are $\frac{1}{6}\text{ft}$ and $\frac{1}{5}\text{ft}$, respectively, then complete the following equations.
Multiplication equation: $\frac{1}{6}\text{ft}\times \frac{1}{5}ft=\frac{\left[\right]}{\left[\right]}\text{sq ft}$
Division equation : $\frac{1}{6}\text{ft}=\frac{\left[\right]}{\left[\right]}\text{sq ft}÷\frac{1}{5}\text{ft}$

Answer 1

The length of the photo frame is $\frac{1}{6}\text{ft},$ and its width is $\frac{1}{5}\text{ft}$.
Area of the photo frame $=$ Length $\times$ Width $=\frac{1}{6}\text{ft}\times \frac{1}{5}\text{ft}=\frac{1\times 1}{6\times 5}=\frac{1}{30}\text{sq ft}$
The multiplication equation:
Quotient $\times$ Divisor $=$ Dividend
Here, quotient $=\frac{1}{6},$ divisor $=\frac{1}{5}$, and dividend $=\frac{1}{30}$
Corresponding or related division equation:
Quotient $=$ Dividend $÷$ Divisor
$\frac{1}{6}\text{ft}=\frac{1}{30}\text{sq ft}÷\frac{1}{5}\text{ft}$
Hence, option B is correct.