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Standing Waves in Open Organ Pipe

If the length...

Question

If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,

then the frequency for the second note is

[CBSE PMT 2002]

A

220 Hz

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B

165 Hz

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C

110 Hz

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D

55 Hz

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Solution

The correct option is B
165 Hz

For closed pipe second note = $\frac{3 v}{4 l} = \frac{3 \times 330}{4 \times 4.5} = 165$ Hz.

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Similar questions

If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s,

then the frequency for the second note is

Q. If the length of a closed organ pipe is 1 m and velocity of sound is 330 m/s, then the frequency for the second note is

Q. The fundamental frequency of a open organ pipe is

300 H z

. The first overtone of this pipe is the same as the first overtone of a closed organ pipe. If the speed of sound be

330 m s^{- 1}

, then the length of the closed organ pipe is

Q. The fundamental frequency of a closed organ pipe is

220 H z

. The second overtone of this pipe has the same wavelength as the third harmonic of an open pipe. Take speed of sound in air

345 m / s

. The length of this pipe is

470 \times 10^{- x} m

x

Q. An open organ pipe has fundamental frequency of

300 Hz

. The first overtone of this organ pipe is same as the first overtone of a closed organ pipe. Find the length of the closed organ pipe?
[speed of sound in air

= 330 m/s

]

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