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If the length...

Question

If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s,

then the frequency for the second note is

A

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B

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C

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D

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Solution

The correct option is B

For closed pipe $n_{1} = \frac{v}{4 l} = \frac{330}{4}$ Hz.

Second note = $3 n_{1} = \frac{3 \times 300}{4}$ Hz.

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