If the length of a cuboid is increased by $25 %$ , breadth is decreased by $20 %$ and height is also decreased by $50 %$ , calculate increase or decrease in volume.

Open in App

Solution

Here, $(1 + \frac{25}{100}) (1 - \frac{20}{100}) (1 - \frac{50}{100}) < 1$
$\frac{5}{4} \times \frac{4}{5} \times \frac{1}{2} < 1$
Hence, volume is decreasing.
Decrease in volume (in percent)
$(1 + \frac{25}{100}) (1 - \frac{20}{100}) (1 - \frac{50}{100} \sim 1) \times 100$
$[\frac{5}{4} \times \frac{4}{5} \times \frac{1}{2} \sim 1] \times 100$
$= 50$ %

Suggest Corrections

Similar questions

The length of a cuboid is $4$ m more than its breadth and $6$ m more than its height. If length increased by $3$ meters, breadth increased by $4$ meters and height decreased by $2$ meters, its volume increased by $512 m^{3}$ . Find the dimensions of the cuboid.

If the length of a rectangle is increased by 5 meters and breadth decreased by 3 meters, the area would decrease by 5 square metres. If the length is increased by 3 meters and breadth increased by 2 meters, the area would increase by 50 square metres. What are the length and breadth?

Q. If the length of a rectangle is increased by