If the length of a minute hand of a wall clock is 7 cm, then the area swept by it in 30 minutes is $c m^{2}$

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Solution

$A r e a s w e p t b y t h e m i n u t e h a n d i n 30 m i n u t e s = \frac{θ}{360} \times π r^{2} W h e r e, θ = A n g l e s u b t e n d e d b y t h e m i n u t e h a n d i n 30 m i n u t e s = 180^{\circ} r = L e n g t h o f t h e m i n u t e h a n d = R a d i u s o f t h e c l o c k A r e a s w e p t b y t h e m i n u t e h a n d = \frac{180^{\circ}}{360^{\circ}} \times \frac{22}{7} \times 7 \times 7 = 77 {c m}^{2}$

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