If the length of a rectangle is increased by 5 meters and breadth decreased by 3 meters, the area would decrease by 5 square metres. If the length is increased by 3 meters and breadth increased by 2 meters, the area would increase by 50 square metres. What are the length and breadth?

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Solution

(l+5)(b-3) = lb - 5
lb - 3l + 5b - 15 = lb -5
-3l + 5b = 10
it can also be written as
3l-5b = -10 ---(1)

(l+3)(b+2) = lb + 50
lb +2l +3b +6= lb +50
2l + 3b = 44 ---(2)

solving 1 and 2,
We get
l=10
b=8

lenght = 10 m
breadth = 8 m

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If the length of a rectangle is increased by 5 meters and breadth decreased by 3 meters, the area would decrease by 5 square metres. If the length is increased by 3 meters and breadth increased by 2 meters, the area would increase by 50 square metres. What are the length and breadth?

(l+5)(b-3) = lb - 5 lb - 3l + 5b - 15 = lb -5 -3l + 5b = 10 it can also be written as 3l-5b = -10 ---(1) (l+3)(b+2) = lb + 50 lb +2l +3b +6= lb +50 2l + 3b = 44 ---(2) solving 1 and 2, We get l=10 b=8 lenght = 10 m breadth = 8 m

(l+5)(b-3) = lb - 5
lb - 3l + 5b - 15 = lb -5
-3l + 5b = 10
it can also be written as
3l-5b = -10 ---(1)

(l+3)(b+2) = lb + 50
lb +2l +3b +6= lb +50
2l + 3b = 44 ---(2)

solving 1 and 2,
We get
l=10
b=8

lenght = 10 m
breadth = 8 m