If the length of a rectangle is "l” and width is "b”, then the perimeter of the rectangle will be

l+b

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2l+b

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l+2b

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2(l+b)

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Solution

The correct option is D
2(l+b)

The perimeter of a rectangle is
$P = 2 \times (l + b)$
Where l = length of a rectangle
b = width of a rectangle

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