Question

If the length of a vernier scale having 25 divisions corresponding to 24 main scale divisions and given that 1 MSD $=$ 1 mm, then the least count of vernier calipers is

• A. 0.004 cm
• B. 4 micrometer
• C. 0.04 mm
• D. 0.04 m

Answer 1

Answer: (A), (C)

The correct options are
A 0.004 cm
C 0.04 mm

Given
N $=$ 25
25 VSD $=$ 24 MSD
1 MSD $=$ 1mm
$\therefore LC=\frac{MSD}{No.ofVSD}=\frac{1mm}{25}$
$=0.04mm$
$=0.04\times {10}^{-1}cm$
$=0.004cm$
$=0.004\times {10}^{-2}m$
$=40\mu m$