Question

If the length of an open organ pipe is 33.3 cm, then the frequency of fifth overtone is: $(V_{sound}=333m/s)$

• A. 3000 Hz
• B. 1500 Hz
• C. 2500 Hz
• D. 1250 Hz

Answer 1

The correct option is A

3000 Hz

Frequency of $5^{th}O.T.=(5+1)\frac{v}{2L}$
$f=\frac{6\times 333}{2\times 33.3\times {10}^{-2}}f=3000Hz$