Question

If the length of diagnal of a cube is $8\sqrt{3}cm$ then its surface area is

$\left(a\right)192c{m}^2\left(b\right)384c{m}^2\left(c\right)512c{m}^2\left(d\right)768c{m}^2$

Answer 1

Let the edge of the cube be a.

so, the diagonal of the cube = $\sqrt{3}a=8\sqrt{3}$

a = 8

Surface area = $6a^2=6\times 8\times 8=384c{m}^2$
option (b)