Question

If the length of each edge of a cube is doubled, what is the change in its total surface area?

Answer 1

let the edge of the cube = a units volume=v=a^3---(1) surface area=6a^2 square units---(2) if length of each edge doubled the new cube edge = 2a units volume = V= (2a)^3=8a^3 = 8×(1) =8 times of the first cube volume surface area = A= 6*(2a)^2 =6×4×a^2 =4×(6a^2) =4×(2) =4 times of the first cube Change in volume=Final - initial = 7 times volume of first cube. Change in Surface are = Final - initial = 3 times surface area of first cube.