Question

If the length of seconds pendulum is increased by $2\%$, how many seconds it will lose per day

• A. 3927s
• B. 3727s
• C. 3427s
• D. 864s

Answer 1

The correct option is D 864s

$T=2\pi \sqrt{\frac{L}{g}}$

$\frac{\Delta T}{T}\times 100=\frac{1}{2}\frac{OL}{L}\times 100$

$=\frac{1}{2}\times 2\%$

$=1\%$

Time period increase by 1%

so one second become 1.01 sec

so gn one day pendulum losses 864 seconds

Hence (D) option is correct answer.