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Question

If the length of subnormal is equal to the length of subtangent at a point (3,4) on the curve y=f(x) and the tangent at (3,4) to y=f(x) meets the coordinate axes at A and B, then twice the value of maximum area of the triangle OAB, where O is origin is:

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Solution

Given: Length of subnormal = length of the subtangent
ydydx=ydxdy
dydx=±1
Equation of the tangent is y4=x3yx=1 or y4=x+3x+y=7

The corresponding intercepts are 1 and 1 or 7 and 7
The area of ΔOAB=12×1×1=12
In the other case, area =12×7×7=492

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