Question

If the length of the diagonal of square is $10\sqrt{2}$ cm then its perimeter is

• A. $10cm$
• B. $40\sqrt{2}cm$
• C. $20cm$
• D. $40cm$

Answer 1

Answer: (D)

$40cm$

Perimeter of square= $4a$

Diagonals of square= $D=\sqrt{2}a$

$\begin{array}{c}\therefore a=\frac{10\sqrt{2}}{\sqrt{2}}=10cm\\ \therefore Perimeter=10\times 4=40cm\end{array}$