Question

If the length of the sides of a right angled triangle are in AP, then their ratio is

Answer 1

Let lengths be $a-d,a,a+d$

$a^2+b^2=c^2$

$(a-d{)}^2+(a{)}^2=(a+d{)}^2$

$a^2=4ad$

$a=4d$

sides are $a-d,a,a+d$ i.e $3d,4d,5d$

Therefore in the ratio $3:4:5$