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Justifying Why Triangles with Certain Specifications Cannot Be Drawn

if the length...

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if the lengths of the sides of a triangle are 3, 5 and 7 , then the largest angle of the triangle i

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Q. If lengths of the sides of triangle are 3,5 and 7, then the largest angle of the triangle is

Q. If the length of the sides of triangle are

3, 5

7

and the largest angle of the triangle is

If the sides of a triangle are in the ratio $2 : \sqrt{6} : (\sqrt{3} + 1)$ , then the largest angle of the triangle will be

Q. The lengths of the sides of a triangle are

(x - y), (x + y)

\sqrt{3 x^{2} + y^{2}}, x, y > 0

. Then the largest angle of the triangle is

\frac{2 π}{3}

Q. If the lengths of the sides of a triangle are in ratio

4 : 5 : 6

and the inradius of the triangle is

3 c m

, then the altitude of the triangle corresponding to the largest side as base is:

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Justifying Why Triangles with Certain Specifications Cannot Be Drawn

Standard VII Mathematics

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