If the lengths of three sides of a triangle are a, b and c, find the perimeter of the triangle.

a+b+c

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3(a+b+c)

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1/2(a+b+c)

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2(a+b+c)

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Solution

The correct option is A a+b+c

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Similar questions

a

b

c

2 a - b - 3, a - b + 1

2 a - 2 b - 1

If a, b and c are the side lengths of the triangle such that $\frac{a + b + c}{a - b - c} = \frac{5}{4}$ .The perimeter of the triangle will be:

a^{2} (b + c - a) + b^{2} (c + a - b) + c^{2} (a + b - c) \leq 3 a b c

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