Question

If the lengths of two diagonals of a rhombus are 15 cm and 41.6 cm, then find its area.

• A. 156 $c{m}^2$
• B. 312 $c{m}^2$
• C. 624 $c{m}^2$
• D. 1248 $c{m}^2$

Answer 1

The correct option is B 312 $c{m}^2$

Given,
Length of one diagonal = 15 cm
Length of other diagonal = 41.6 cm

We know that,
Area of a rhombus
$=\frac{1}{2}\times \left(productofdiagonals\right)$

$=\frac{1}{2}$$\times$(15$\times$41.6)

$=\frac{1}{2}\times \left(15\right)\times \frac{416}{10}$

$=\frac{1}{2}\times \left(3\right)\times \frac{416}{2}$

$=\frac{1}{2}$$\times$(624)

= 312 $c{m}^2$