Question

If the letter of the word "ATTEMPT" are written down at random then the probability that all the T's are consecutive is

• A. $\frac{1}{42}$
• B. $\frac{6}{7}$
• C. $\frac{1}{7}$
• D. $\frac{1}{6}$

Answer 1

The correct option is A $\frac{1}{42}$

$ATTEMPT$

$7$ letters

Total combinations $=7!$

If all $7$ are consecutive then total considering $5$ letters combination $=5!$

Probability $=\frac{5!}{7!}=\frac{5!}{7\times 6\times 5!}=\frac{1}{42}$ Answer (A)