Question

If the letters of the word ATTEMPT are written down at random, the chance that all $T^{\prime }s$ are consecutive is

• A. $\frac{1}{42}$
• B. $\frac{6}{7}$
• C. $\frac{1}{7}$
• D. none of these

Answer 1

The correct option is C $\frac{1}{7}$

Total no of word that can be formed from 'ATTEMPT' =$\frac{7!}{3!}$
The no words when all T's are consecutive =5!
Hence probability=$\frac{5!}{\frac{7!}{3!}}=\frac{5!\times 3!}{7!}=\frac{6}{7\times 6}=\frac{1}{7}$