Question

If the letters of the word CHASM are rearranged to form $5$ letter words such that none of the word repeat and the results arranged in ascending order as in a dictionary what is the rank of the word CHASM?

• A. $24$
• B. $31$
• C. $30$
• D. $32$

Answer 1

The correct option is D $32$

Given word is $CHASM$

Alphabetical order $ACHMS$

Number of words begning with $A=4!=24$

Number of words begning with $CH=3!=6$

Number of words begning with $CHAM=1!=1$

Number of words begning with $CHASM=0!=1$

Hence the correct answer is $32$